0=x^2+108-39x

Solution for 0=x^2+108-39x equation:

0=x^2+108-39x

We move all terms to the left:

0-(x^2+108-39x)=0

We add all the numbers together, and all the variables

-(x^2+108-39x)=0

We get rid of parentheses

-x^2+39x-108=0

We add all the numbers together, and all the variables

-1x^2+39x-108=0

a = -1; b = 39; c = -108;
Δ = b2-4ac
Δ = 392-4·(-1)·(-108)
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-33}{2*-1}=\frac{-72}{-2}
=+36
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+33}{2*-1}=\frac{-6}{-2}
=+3
$